December 2003 - cypherpunks-legacy

Object code disassembly (was Re: [LONG, off-topic]] Interactive Programming)
by nobody＠REPLAY.COM 17 Dec '03

17 Dec '03

> It worked. After a few iterations of this I had all the entry points, and > everything that didn't disassemble cleanly was outputted as hex data. > > For fun, run objdump on a cleanly compiled unix binary... It makes it all > look so easy... :) Not quite that easy. Awhile back I disassembled RealAudio because I was curious how their codec worked. Turns out it was not all that interesting and the codecs in nautilus and speak freely are probably better. But anyway.... Running objdump on the binary spit out ~800000 lines of code. They statically linked the whole thing, motif, c library, and all. I'm not sure what they compiled it with, the c-library they had in there didn't look like any of the standard ones. It disassembled fine, but 800k lines of assembler dump is not really all that readable. So I ended up doing it interactively, setting breakpoints on the I/O operations and backtracing to find the coder. The user interface code tended to get in the way a lot. The 1kb/s coder is very basic. No predictor/corrector, and no redundancy (eg lempel-ziv, rle) compression at all. It's just a frequency/band coder at 10 frames per second. I guess thats so it can handle dropped frames. No checksums at all. The "28.8" codec is more sophisticated. It appears to be a LPC and compresses data into much larger blocks/packets. I didn't look into it too deeply because there are lots of other lpc coders available. Shortly after this, they put out a new version 3.0, with yet another codec, which I never looked at. This was quite awhile ago, and all this is from memory. So the codec was rather uninteresting, but there were a number of other "features" which got my attention. I looked at the network protocol. Its pretty simple. The client connects to the server and requests the file it wants. It also sends a whole bunch of other info, like host operating system, version number, etc. ("for statistical purposes, right? uh huh..." are you guys over there at anonymizer.com reading this? hint, hint.) Then it does something truly bizarre. The client and server exchange 32-digit hex numbers. The client calls gettimeofday() and gethostname() and uses this as a random seed. Then it sends a 128-bit random number, encoded as 32 ascii hex digits. The server does the same. I haven't a clue what this is for. Considering that the other data structures are all binary, sending this as ascii is really dumb. It looks as though its part of some third-party library. I thought maybe it was some variant of netscape cookies but it doesn't save anything to disk. It's just wierd. I tried stepping through this section of code a few times, but doing so usually caused the server to time-out. Then the server starts sending the audio file as one big stream of packets - same format as the files it saves to disk, just broken up into packets, each preceeded by a length byte. In udp mode the client sends acks every second or so. In tcp mode there are no in-band acks at all, it relies solely on the tcp protocol driver. No checksums on anything, and it uses predictable port numbers. You can probably spoof it real easy. That might make for an interesting prank.

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Re: What's really in PGP 5.5?
by Anonymous 17 Dec '03

17 Dec '03

The danger with the PGP system is that it could be easily perverted into a British style trusted-third-party system for GAK. The government would set up a key management infrastructure to provide an official repository and CA to register keys. It could even be "voluntary" if only government-approved CAs had liability protection which private CAs didn't have, making it hard for the privates to compete. However the price to use the government registry is that each key has to use the PGP features to specify a TTP as an additional recipient. Every message encrypted to that key should also be encrypted to the TTP key. Only government-approved TTPs may be used, and although there are many to choose from, all have to provide easy and secret GAK. The PGP 5 software will then automatically encrypt to the TTP key. Yes, this can be defeated using superencryption or faking the additional-recipient block in the message. But we know any scheme can be defeated. It still satisfies the government's requirement to get routine access to most email communications, and to allow criminals who use standard email packages to be watched.

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Defeating MITM with Eric's Secure Phone
by John Kelsey 17 Dec '03

17 Dec '03

-----BEGIN PGP SIGNED MESSAGE----- [ To: cypherpunks, coderpunks, Perry's Crypto List ## Date: 09-Oct-97 ## Subject: Defeating MITM with Eric's Secure Phone ] >Date: Wed, 8 Oct 1997 23:48:33 +0100 >From: Adam Back <aba(a)dcs.ex.ac.uk> >Subject: computationally infeasible jobs for MITMs (Re: Secure phone) >How about this for a computerised method to do something similar. Aim >of the game: to make the MITMs job computationally infeasible. [Method using stegoed audio noise deleted.] I prefer to work on the more immediately useful problem: How can I secure my use of the (very nicely done) Comsec secure phones using existing infrastructure? I am concerned with the MITM voice impersonation attack, since that's the easiest attack on the system. (Actually, it's probably easier to physically tap my office, but I can't fix that right now.) The simple MITM defenses (like restating your checksum spontaneously in the middle of the conversation) take care of lots of this. Here's another way that may make some sense, though it's a little hard to use: 1. Exchange PGP-encrypted e-mail establishing a set of sixteen different words, labeled for 0..f in each direction. Thus: 0. Dilbert 1. Alpha 2. Cable 3. Swordsman ... f. Marxist Now, the checksum reading is very hard to spoof. Suppose I get 0x33f. I say ``My checksum is Swordsman Swordsman Marxist, or 33f.'' An attacker with digits besides 3 and f in his checksum simply doesn't know how to impersonate me to the other party. He lacks the secret information we've shared. Now, the problem with this is that it's too cumbersome. I would like the shared secret information to be usable with less effort. If we just want to detect the MITM eventually, then I can send the other participant a PGP-signed e-mail, in which I include the whole 6-digit checksum. That won't prevent the MITM attack from working once, but it will let us know after-the-fact if our conversation was exposed. If we find evidence that our conversation was intercepted, then we can start using my one-time word lists, or some other more paranoid mechanism. Still another approach, which may be applicable for some people, is to write a simple calculator-type application that uses a shared-secret to compute a checksum on the checksum. Thus, when I call Alice, I do the following: 1. Type the shared secret between Alice and me into the calculator app. 2. Make the call to Alice and push the ``secure'' button. 3. Type the six-digit checksum into the calculator app. 4. Read the calculator's first three checksum digits. 5. Listen to her next three digits. The simplest way to do this seems to be to just exchange a six-digit hex value as a one-time password for a given secure phone call. This is done using PGP or some other mail encryption package, and can legitimately be used to exchange a long list of one-time passwords at once. Then, use Windows' calculator application (with View set to Scientific, and Mode set to Hex) to add your one-time password to the checksum. Thus: 1. I pull up Alice's latest encrypted e-mail, and get today's phone password. 2. I open the Windows calculator, set it to View/Scientific and hex mode, and type in the password (a six-digit hex number) and ``+.'' 3. I call Alice, say hello, and push the ``SECURE'' button. 4. I type the six digit hex checksum into my calculator. 5. I read the first three digits of the result to her. She reads the next three to me. All of this (except for maybe re-reading the checksum in the middle of the conversation) is probably overkill. Still, it may be worth something to someone. Is there a clean way to have the secure phone box take input from the dialpad on the phone, without sending it out on the phone line? If so, then maybe some later version could include a PIN-secured mode, using EKE or SPEKE or something similar. (For a supported mode, the checksum wouldn't need to be read over the phone anymore. We would need to protect the shared PIN from brute-force attack, however.) >Adam --John Kelsey, jmkelsey(a)plnet.net / kelsey(a)counterpane.com - -----BEGIN PGP PUBLIC KEY BLOCK----- Version: 2.6.2 mQCNAi5JqlEAAAEEAPCEHMBdDCAJ83/ibNM7ngCaaibv7YkTxcpKPjTO+WcjswFV SEzMeTqW4MX2wSKdfcMq1HembbgfYs7v2UCnUFkLPZF19s3yUSISGcS7JxlBc3q1 7uj8W5XfBoGpgCYQqYFL2+AB/+3tLu7lU5iiEYCnevY5GQkq0kHx57Ag8goBAAUR tCdKb2huIE0uIEtlbHNleSBKciA8am1rZWxzZXlAZGVscGhpLmNvbT6JAJUDBRAv 5uh7QfHnsCDyCgEBAQZ2A/9/OMeWK4YC+PnEzBTmgpF4WAOsVXfzRD3zAbzfNWY9 MEGo4gRF8Mr1lPHdK+0JOHp327mj9ZvYqQb1bV5fwc5dJa8/Z34VLPYlVg2rV7vJ Hd0YnrgkoaIerbRmtP8dmZGeygeFtrk8aDCdcnMm27+tTJACl5hv2yjFO9rxBq+R MLQpRXhwaXJlcyBmb3IgbmV3IHNpZ3MvbXNncyBvbiBEZWMgMzEsIDE5OTc= =pOyw - -----END PGP PUBLIC KEY BLOCK----- -----BEGIN PGP SIGNATURE----- Version: 2.6.2 iQCVAwUBNDy68UHx57Ag8goBAQGP1QP9H6Z9Infv1z1swBzpEsvn+VZyweMj20to EQNRFcfLvNFu140kWokWfgIcSXh1CBrsz93/CMoZgIb8l1cpGIU51kFgz/DTXGvj 5XQCFcUzBRAEraxeF7xFnEH+Ss35lcCvzAXaWaVLB6apBvXP5ZkZtFr/vUYLhrtF Y34E8AAXFrg= =AlX3 -----END PGP SIGNATURE----- --John Kelsey, Counterpane Systems, kelsey(a)counterpane.com PGP 2.6 fingerprint = 4FE2 F421 100F BB0A 03D1 FE06 A435 7E36

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Applying ``Crowds'' idea to anonymous e-cash.
by John Kelsey 17 Dec '03

17 Dec '03

-----BEGIN PGP SIGNED MESSAGE----- [ To: cypherpunks, coderpunks, Perry's Crypto List ## Date: 10/09/97 ## Subject: Applying ``Crowds'' idea to anonymous e-cash. ] I was thinking about applying the ``Crowds'' idea to anonymous e-cash, and came up with what I think is a pretty good idea. I am interested in seeing if anyone sees either holes in it, or ways to improve it. I am also interested in hearing about whether or not it has been invented before. Crowds, for those who haven't seen it, is a way of giving web users partial anonymity by making it impossible to determine which member of some ``crowd'' of users did some action (such as requesting a document). (This is a very rough summary--read the paper for the real analysis.) I can see a way to do something very similar with withdrawing electronic coins. (This works best with online-cleared coins), without any blinding being used. I think this gets around the Chaum patents. I also think it can probably be implemented more-or-less on top of the web-anonymizing Crowds stuff, though I may be wrong. Here's the basic idea: 1. A Crowd of users forms up, each wanting to withdraw some reasonably large amount of money, such as $100, in $1 e-coins. 2. Each user provides a public key and pays some money (perhaps $101) into the bank. The bank registers each public key as belonging to a member of the crowd. 3. Each member of the crowd is given all other members' public keys. 4. Each member prepares 100 one-use symmetric encryption keys, each with a 64-bit key ID. 5. The members organize themselves into a sort of one-time anonymous routing network, using those public keys. Each message to be sent is encrypted in layers (a la onion routing), so that each member appears at least once in the message's path. Each message ends up at the bank, eventually. I'll talk about likely network architectures later, if anyone's interested. 6. The bank publishes something noting that it has received N*100 keys, where N = the number of members in the crowd. It also publishes the hashes of all N*100 symmetric keys. 7. Each member digitally signs something saying that he agrees with the keys published, he hasn't been railroaded, etc. Nothing proceeds until this has been published from each member. 8. The bank encrypts one $1 online-cleared e-coin under each symmetric key. It publishes a list of (key ID, encrypted coin) pairs for all the members to receive. 9. Each member walks away with $100 in $1 e-coins. Nobody can prove which member got which coin. No linking of coins is possible. Now, the protocol isn't all *that* important here, but the idea is: We interface with the traceable money world, but grant a sort of weak anonymity for all users in the crowd. Because the coins are online-cleared, they must be deposited immediately. To protect recipient-confidentiality, these can be deposited under a pseudonym account--basically just a one-use public key. The recipient accumulates a bunch of credit under that public key, and then goes through the withdrawal procedure again to get new, weakly anonymous coins, which he can openly deposit without direct traceability. (That is, the bank can still learn that certain coins were spent at the same place, but can't identify the final recipient of the money. I can think of ways to adapt this idea to unlinkability, though they involve some implementation hassles.) Note that multiple iterations of the withdrawal protocol make things much stronger. That is, there is no reason why the participants in the withdrawal protocol have to spend their e-coins directly--they can also use them, along with a one-use public key, to go back into the withdrawal protocol again. An attacker who manages to link a given coin to a given crowd (possible only with the help of the bank) with some anonymous participants (who paid in with coins from this scheme) must face the possibility that this coin could have come from the anonymous participants--which can then be traced to another pool, with other anonymous participants, etc. The attacker can't even make statistical statements in many cases, since, if I were doing something really hot, I'd want to go through the withdrawal process lots of times. The bank can tell only what crowd your coins came from, not how many times you have swapped your coins out. If you're willing to pay the transaction costs and time, you can withdraw and deposit as many times as you like. Comments? Is this idea practical at all? Has someone else already done it? --John Kelsey, jmkelsey(a)plnet.net / kelsey(a)counterpane.com - -----BEGIN PGP PUBLIC KEY BLOCK----- Version: 2.6.2 mQCNAi5JqlEAAAEEAPCEHMBdDCAJ83/ibNM7ngCaaibv7YkTxcpKPjTO+WcjswFV SEzMeTqW4MX2wSKdfcMq1HembbgfYs7v2UCnUFkLPZF19s3yUSISGcS7JxlBc3q1 7uj8W5XfBoGpgCYQqYFL2+AB/+3tLu7lU5iiEYCnevY5GQkq0kHx57Ag8goBAAUR tCdKb2huIE0uIEtlbHNleSBKciA8am1rZWxzZXlAZGVscGhpLmNvbT6JAJUDBRAv 5uh7QfHnsCDyCgEBAQZ2A/9/OMeWK4YC+PnEzBTmgpF4WAOsVXfzRD3zAbzfNWY9 MEGo4gRF8Mr1lPHdK+0JOHp327mj9ZvYqQb1bV5fwc5dJa8/Z34VLPYlVg2rV7vJ Hd0YnrgkoaIerbRmtP8dmZGeygeFtrk8aDCdcnMm27+tTJACl5hv2yjFO9rxBq+R MLQpRXhwaXJlcyBmb3IgbmV3IHNpZ3MvbXNncyBvbiBEZWMgMzEsIDE5OTc= =pOyw - -----END PGP PUBLIC KEY BLOCK----- -----BEGIN PGP SIGNATURE----- Version: 2.6.2 iQCVAwUBNDzFQkHx57Ag8goBAQHYkQQA0Oud9OvEX7qJdxJgGyirqzrAN4jI005p aOVl9UnSf4XGEPj1DFMONW61HaLoh46tEDmnfMrXjI706IfwNF3HfY14FIrGe5Nb U386CP5iztc6rpS6YsiX+prN9Q9RIXzari9uSHrmYSlGAcqa571vy7kkn7uejGBC jv+0hnYNE1M= =aHpr -----END PGP SIGNATURE----- --John Kelsey, Counterpane Systems, kelsey(a)counterpane.com PGP 2.6 fingerprint = 4FE2 F421 100F BB0A 03D1 FE06 A435 7E36

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Improper biometric controls...
by Robert Hettinga 17 Dec '03

17 Dec '03

--- begin forwarded text Resent-Date: Thu, 9 Oct 1997 11:55:35 -0400 X-Authentication-Warning: qnx.com: localhost [127.0.0.1] didn't use HELO protocol To: 0xdeadbeef(a)substance.abuse.blackdown.org Cc: bostic(a)bsdi.com Subject: Exam tip o' the day Date: Thu, 09 Oct 1997 11:50:58 -0400 From: glen mccready <glen(a)qnx.com> Resent-From: 0xdeadbeef(a)substance.abuse.blackdown.org X-Mailing-List: <0xdeadbeef(a)substance.abuse.blackdown.org> archive/latest/2317 X-Loop: 0xdeadbeef(a)substance.abuse.blackdown.org Precedence: list Resent-Sender: 0xdeadbeef-request(a)substance.abuse.blackdown.org Forwarded-by: Rob Windsor <windsor(a)oc.com> Forwarded-by: Kirk A Schneider <kschneid(a)oc.com> It was the week of finals, and obviously, everyone was stressing. This happened in a big (+300) lecture class, it was some hard science course with one of those real pain-in-the ass professors. Everyone taking this course had been dreading this final from the start. They all knew they had no hope. There was one student in the class who felt confident in the area if he could just take his time and work his way through each problem. So, on the day of the final, he decided he would just take his time on the test. The exam began, and he slowly paced himself, carefully working out each problem. This was diffficult because the professor was one of those guys who would obnoxiously yell to the class how much time they had left every three minutes. He was just one of those guys who needed a smack in the face. Finally, time was up, and the teacher told the class to stop, and to bring their test papers down to his desk. With over three-hundred people, this procedure took quite a while. That one student just continued working on his test. Eventually, ten extra minutes turned into twenty, until the student was there for almost an hour after the exam had ended. He looked at his paper, and decided he had completed the test to his satisfaction, and he could now hand it in. He gathered his things and walked down to the teachers desk. The professor was sitting at the desk, the tests were still sitting on the desk in a neatly stacked pile, and it was clear he had just been waiting for this student to finish so that he could tell him that he had failed. The student reached his professors desk with a big smile on his face. The professor said to him, "This test was due an hour ago. By handing it in now it is considered late, and consequently, you fail." The student looked right at the professor and said to him "Do you know who I am?" The professor clearly upset by his student's response said "What are you talking about?" Again the student said, "Do you know who I am?" The professor responded by saying no, of course not... Just as he said this, the student lifted up half of the test papers still sitting on the teachers desk. He casually slipped his test on the pile, and let the rest of the tests fall naturally back onto the stack. He looked at his professor and said "I didn't think so." --- end forwarded text ----------------- Robert Hettinga (rah(a)shipwright.com) Philodox e$, 44 Farquhar Street, Boston, MA 02131 USA "... however it may deserve respect for its usefulness and antiquity, [predicting the end of the world] has not been found agreeable to experience." -- Edward Gibbon, 'Decline and Fall of the Roman Empire' The e$ Home Page: http://www.shipwright.com/ Ask me about FC98 in Anguilla!: <http://www.fc98.ai/>

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Secure Phone: Making man in the middle audible.
by James A. Donald 17 Dec '03

17 Dec '03

Here is a method to render Man in the Middle audible on a telephone connection. Before speech can be encrypted, it is digitized and compressed. It is turned into digital packets. There is some choice in the size and other properties of the digital packets. Suppose that Bob's computer from time to time formulates a plan to do groups of a particular size and form, and sends Ann's computer a hash of that plan and the DH negotiated shared secret. Malloc (the man in the middle) cannot send this hash to Ann's computer for Ann would discover the shared secret she is using is not the same as the shared Bob is using. So his computer must formulate its own plan, and send its own hash, which will not agree with Bob's plan, because Bob's computer does not reveal the plan except by actually sending the packets. So malloc must decompress Bob's speech packets, repacketize them, and recompress them, Often he will not be able to send off a packet, until he has received two of Bob's packets. So this triples the delay, and increases the speech degradation. This should quite noticeable, noticeable enough to provoke Bob and Ann into verifying their connection by reading the hash digits of their shared secret. --------------------------------------------------------------------- | We have the right to defend ourselves | http://www.jim.com/jamesd/ and our property, because of the kind | of animals that we are. True law | James A. Donald derives from this right, not from the | arbitrary power of the state. | jamesd(a)echeque.com

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RE: EU Rejects GAK
by Phillip Hallam-Baker 17 Dec '03

17 Dec '03

Before people get carried away it is important to realise that the EU institutions do not map onto US ones. The EU Commission does not have an analogue in the US system. It is an unelected group of beureacrats whose purpose is (roughly speaking) to harmonize EU law. It does not have legislative powers in its own right, nor does it necessarily have much influence. The EU lawmaking process is essentially that the Commision drafts some suggestions and passes them onto the council of ministers which accepts, rejects or ammends them. If there is unanimous agreement in the concil of ministers (majority vote on a restricted number of issues) then a directive is issued which the national parliaments must then enact into law. The limited scope of EU laws is critical, the EU is much like the US prior to the civil war, the member states are sovereign. Thus there is nothing the EU Commission can do to prevent member states outlawing crypto, nor for that matter can they force them to allow it. They can assist in forming EU wide regulations either way however. The real importance of the EU report is probably that it denies the statements made by the Freeh et. al. claiming that US alies in Europe are in favour of GAK. Despite the fact that there has never been any public demonstration of a commitment the administration has disingenuously claimed that it has the support of and indeed is being pressured to take its stance on export controls by other countries. Needless to say it is unconvincing to be told 'trust me' by someone who is clearly peddling a lie. Few people can prove it is a lie because few people can claim to have the personal access to European politicians the administration can. I know UK politics well enough to know that the current parliament is not going to back any increase of powers for a security service that many members of the government was used politically by the Conservatives. It would be like the nation of Islam calling for arbitrary arrest powers for the police. Phill

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Re: 6502 ML programming
by Anonymous 17 Dec '03

17 Dec '03

If you guys are still doing 6502 work, maybe you can make use of this. -- * RSA Data Security, Inc. MD5 Message-Digest Algorithm * * *********************************************************************** * ** Message-digest routines: ** * ** To form the message digest for a message M ** * ** (1) Initialize a context buffer mdContext using MD5Init ** * ** (2) Call MD5Update on mdContext and M ** * ** (3) Call MD5Final on mdContext ** * ** The message digest is now in the bugffer passed to MD5Final ** * *********************************************************************** * ORG $2000 * Jump Table JMP MD5INIT JMP MD5UPD JMP MD5FINAL DIGEST HEX 00000000 ;Message digest ends up here. HEX 00000000 HEX 00000000 HEX 00000000 MD5INITV HEX 01234567 ;MD5 initialization values HEX 89ABCDEF HEX FEDCBA98 HEX 76543210 MD5BYTES DS 8 ;Counts bytes in message digest so far MD5BUFRP HEX 00 ;Pointer to current byte in partially full buffer MD5BUFR DS 64 ;64-byte buffer for current MD5 block * Initialize MD5 - start new message digest MD5INIT LDX #15 ;Load initialization constants ]LOOP LDA MD5INITV,X STA DIGEST,X DEX BPL ]LOOP LDA #0 ;Reset byte count to zero LDX #7 ]LOOP STA MD5BYTES,X DEX BPL ]LOOP STA MD5BUFRP ;Reset buffer to empty ]RTS RTS * MD5UPD - add a byte to the message digest MD5UPD LDX MD5BUFRP STA MD5BUFR,X INX STX MD5BUFRP JSR INCBYTES CPX #64 BCC ]RTS LDX #0 STX MD5BUFRP JSR MD5DOBLK RTS INCBYTES INC MD5BYTES BNE ]RTS INC MD5BYTES+1 BNE ]RTS INC MD5BYTES+2 BNE ]RTS HEX 0000 * MD5FINAL - do last block and compute final digest MD5FINAL LDA #$80 LDX MD5BUFRP STA MD5BUFR,X INX STX MD5BUFRP ]LOOP CPX #64 BCC MD5FA LDX #0 STX MD5BUFRP JSR MD5DOBLK MD5FA LDX MD5BUFRP LDA #0 STA MD5BUFR,X INX STX MD5BUFRP CPX #56 BNE ]LOOP LDA MD5BYTES STA MD5BUFR+56 LDA MD5BYTES+1 STA MD5BUFR+57 LDA MD5BYTES+2 STA MD5BUFR+58 LDA MD5BYTES+3 STA MD5BUFR+59 LDA MD5BYTES+4 STA MD5BUFR+60 LDA MD5BYTES+5 STA MD5BUFR+61 LDA MD5BYTES+6 STA MD5BUFR+62 LDA MD5BYTES+7 STA MD5BUFR+63 LUP 3 ;Multiply times 8 LDA MD5BUFR+56 ; to convert number of bytes to number of bits ASL STA MD5BUFR+56 LDA MD5BUFR+57 ROL STA MD5BUFR+57 LDA MD5BUFR+58 ROL STA MD5BUFR+58 LDA MD5BUFR+59 ROL ;Unlikely the message would be over 500 MB STA MD5BUFR+59 ;so we can stop here... --^ JSR MD5DOBLK RTS MD5TEMPB DS 16 ;Temporary buffer for a,b,c,d MD5TEMPV DS 4 ;Temporary 32-bit word storage (used by MD5DOBLK) MD5TEMP2 DS 4 ;Temporary 32-bit variable #2 (used by F,G,H,I fcns) * Block transformation MD5DOBLK LDX #15 ;Copy values into temp buffer ]LOOP LDA DIGEST,X STA MD5TEMPB,X DEX BPL ]LOOP LDA #0 STA MD5TP * Round 1 : F-functions * a = b + ((a + F(b,c,d) + X[k] + T[i]) <<< s). */ JSR MD5LOADA ;1 (a,b,c,d) JSR F_BCD JSR NEXT_T ;(D76AA478) LDA #0 JSR MD5ADDX JSR MD5RL7 ;Rotate Left 7 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;2 (d,a,b,c) JSR F_ABC JSR NEXT_T ;(E8C7B756) LDA #1 JSR MD5ADDX JSR MD5RL12 ;Rotate Left 12 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;3 (c,d,a,b) JSR F_DAB JSR NEXT_T LDA #2 JSR MD5ADDX JSR MD5RL17 ;Rotate left 17 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;4 (b,c,d,a) JSR F_CDA JSR NEXT_T LDA #3 JSR MD5ADDX JSR MD5RL22 ;Rotate left 22 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;5 (a,b,c,d) JSR F_BCD JSR NEXT_T LDA #4 JSR MD5ADDX JSR MD5RL7 ;<<7 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;6 (d,a,b,c) JSR F_ABC JSR NEXT_T LDA #5 JSR MD5ADDX JSR MD5RL12 ;<<12 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;7 (c,d,a,b) JSR F_DAB JSR NEXT_T LDA #6 JSR MD5ADDX JSR MD5RL17 ;<<17 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;8 (b,c,d,a) JSR F_CDA JSR NEXT_T LDA #7 JSR MD5ADDX JSR MD5RL22 ;<<22 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;9 (a,b,c,d) JSR F_BCD JSR NEXT_T LDA #8 JSR MD5ADDX JSR MD5RL7 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;10 (d,a,b,c) JSR F_ABC JSR NEXT_T LDA #9 JSR MD5ADDX JSR MD5RL12 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;11 (c,d,a,b) JSR F_DAB JSR NEXT_T LDA #10 JSR MD5ADDX JSR MD5RL17 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;12 (b,c,d,a) JSR F_CDA JSR NEXT_T LDA #11 JSR MD5ADDX JSR MD5RL22 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;13 (a,b,c,d) JSR F_BCD JSR NEXT_T LDA #12 JSR MD5ADDX JSR MD5RL7 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;14 (d,a,b,c) JSR F_ABC JSR NEXT_T LDA #13 JSR MD5ADDX JSR MD5RL12 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;15 (c,d,a,b) JSR F_DAB JSR NEXT_T LDA #14 JSR MD5ADDX JSR MD5RL17 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;16 (b,c,d,a) JSR F_CDA JSR NEXT_T LDA #15 JSR MD5ADDX JSR MD5RL22 JSR MD5ADDC JSR MD5STORB * Round 2 : G-functions * a = b + ((a + G(b,c,d) + X[k] + T[i]) <<< s). */ JSR MD5LOADA ;17 (a,b,c,d) JSR G_BCD JSR NEXT_T LDA #1 JSR MD5ADDX JSR MD5RL5 ;Rotate Left 5 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;18 (d,a,b,c) JSR G_ABC JSR NEXT_T LDA #6 JSR MD5ADDX JSR MD5RL9 ;Rotate Left 9 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;19 (c,d,a,b) JSR G_DAB JSR NEXT_T LDA #11 JSR MD5ADDX JSR MD5RL14 ;Rotate left 14 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;20 (b,c,d,a) JSR G_CDA JSR NEXT_T LDA #0 JSR MD5ADDX JSR MD5RL20 ;Rotate left 20 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;21 (a,b,c,d) JSR G_BCD JSR NEXT_T LDA #5 JSR MD5ADDX JSR MD5RL5 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;22 (d,a,b,c) JSR G_ABC JSR NEXT_T LDA #10 JSR MD5ADDX JSR MD5RL9 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;23 (c,d,a,b) JSR G_DAB JSR NEXT_T LDA #15 JSR MD5ADDX JSR MD5RL14 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;24 (b,c,d,a) JSR G_CDA JSR NEXT_T LDA #4 JSR MD5ADDX JSR MD5RL20 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;25 (a,b,c,d) JSR G_BCD JSR NEXT_T LDA #9 JSR MD5ADDX JSR MD5RL5 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;26 (d,a,b,c) JSR G_ABC JSR NEXT_T LDA #14 JSR MD5ADDX JSR MD5RL9 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;27 (c,d,a,b) JSR G_DAB JSR NEXT_T LDA #3 JSR MD5ADDX JSR MD5RL14 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;28 (b,c,d,a) JSR G_CDA JSR NEXT_T LDA #8 JSR MD5ADDX JSR MD5RL20 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;29 (a,b,c,d) JSR G_BCD JSR NEXT_T LDA #13 JSR MD5ADDX JSR MD5RL5 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;30 (d,a,b,c) JSR G_ABC JSR NEXT_T LDA #2 JSR MD5ADDX JSR MD5RL9 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;31 (c,d,a,b) JSR G_DAB JSR NEXT_T LDA #7 JSR MD5ADDX JSR MD5RL14 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;32 (b,c,d,a) JSR G_CDA JSR NEXT_T LDA #12 JSR MD5ADDX JSR MD5RL20 JSR MD5ADDC JSR MD5STORB * Round 3 : H-functions * a = b + ((a + H(b,c,d) + X[k] + T[i]) <<< s). */ JSR MD5LOADA ;33 (a,b,c,d) JSR H_BCD JSR NEXT_T LDA #5 JSR MD5ADDX JSR MD5RL4 ;Rotate Left 4 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;34 (d,a,b,c) JSR H_ABC JSR NEXT_T LDA #8 JSR MD5ADDX JSR MD5RL11 ;Rotate Left 11 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;35 (c,d,a,b) JSR H_DAB JSR NEXT_T LDA #11 JSR MD5ADDX JSR MD5RL16 ;Rotate left 16 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;36 (b,c,d,a) JSR H_CDA JSR NEXT_T LDA #14 JSR MD5ADDX JSR MD5RL23 ;Rotate left 23 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;37 (a,b,c,d) JSR H_BCD JSR NEXT_T LDA #1 JSR MD5ADDX JSR MD5RL4 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;38 (d,a,b,c) JSR H_ABC JSR NEXT_T LDA #4 JSR MD5ADDX JSR MD5RL11 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;39 (c,d,a,b) JSR H_DAB JSR NEXT_T LDA #7 JSR MD5ADDX JSR MD5RL16 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;40 (b,c,d,a) JSR H_CDA JSR NEXT_T LDA #10 JSR MD5ADDX JSR MD5RL23 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;41 (a,b,c,d) JSR H_BCD JSR NEXT_T LDA #13 JSR MD5ADDX JSR MD5RL4 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;42 (d,a,b,c) JSR H_ABC JSR NEXT_T LDA #0 JSR MD5ADDX JSR MD5RL11 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;43 (c,d,a,b) JSR H_DAB JSR NEXT_T LDA #3 JSR MD5ADDX JSR MD5RL16 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;44 (b,c,d,a) JSR H_CDA JSR NEXT_T LDA #6 JSR MD5ADDX JSR MD5RL23 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;45 (a,b,c,d) JSR H_BCD JSR NEXT_T LDA #9 JSR MD5ADDX JSR MD5RL4 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;46 (d,a,b,c) JSR H_ABC JSR NEXT_T LDA #12 JSR MD5ADDX JSR MD5RL11 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;47 (c,d,a,b) JSR H_DAB JSR NEXT_T LDA #15 JSR MD5ADDX JSR MD5RL16 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;48 (b,c,d,a) JSR H_CDA JSR NEXT_T LDA #2 JSR MD5ADDX JSR MD5RL23 JSR MD5ADDC JSR MD5STORB * Round 4 : I-functions * a = b + ((a + I(b,c,d) + X[k] + T[i]) <<< s). */ JSR MD5LOADA ;49 (a,b,c,d) JSR I_BCD JSR NEXT_T LDA #0 JSR MD5ADDX JSR MD5RL6 ;Rotate Left 6 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;50 (d,a,b,c) JSR I_ABC JSR NEXT_T LDA #7 JSR MD5ADDX JSR MD5RL10 ;Rotate Left 10 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;51 (c,d,a,b) JSR I_DAB JSR NEXT_T LDA #14 JSR MD5ADDX JSR MD5RL15 ;Rotate left 15 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;52 (b,c,d,a) JSR I_CDA JSR NEXT_T LDA #5 JSR MD5ADDX JSR MD5RL21 ;Rotate left 21 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;53 (a,b,c,d) JSR I_BCD JSR NEXT_T LDA #12 JSR MD5ADDX JSR MD5RL6 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;54 (d,a,b,c) JSR I_ABC JSR NEXT_T LDA #3 JSR MD5ADDX JSR MD5RL10 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;55 (c,d,a,b) JSR I_DAB JSR NEXT_T LDA #10 JSR MD5ADDX JSR MD5RL15 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;56 (b,c,d,a) JSR I_CDA JSR NEXT_T LDA #1 JSR MD5ADDX JSR MD5RL21 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;57 (a,b,c,d) JSR I_BCD JSR NEXT_T LDA #8 JSR MD5ADDX JSR MD5RL6 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;58 (d,a,b,c) JSR I_ABC JSR NEXT_T LDA #15 JSR MD5ADDX JSR MD5RL10 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;59 (c,d,a,b) JSR I_DAB JSR NEXT_T LDA #6 JSR MD5ADDX JSR MD5RL15 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;60 (b,c,d,a) JSR I_CDA JSR NEXT_T LDA #13 JSR MD5ADDX JSR MD5RL21 JSR MD5ADDC JSR MD5STORB JSR MD5LOADA ;61 (a,b,c,d) JSR I_BCD JSR NEXT_T LDA #4 JSR MD5ADDX JSR MD5RL6 JSR MD5ADDB JSR MD5STORA JSR MD5LOADD ;62 (d,a,b,c) JSR I_ABC JSR NEXT_T LDA #11 JSR MD5ADDX JSR MD5RL10 JSR MD5ADDA JSR MD5STORD JSR MD5LOADC ;63 (c,d,a,b) JSR I_DAB JSR NEXT_T LDA #2 JSR MD5ADDX JSR MD5RL15 JSR MD5ADDD JSR MD5STORC JSR MD5LOADB ;64 (b,c,d,a) JSR I_CDA JSR NEXT_T LDA #9 JSR MD5ADDX JSR MD5RL21 JSR MD5ADDC JSR MD5STORB * Add value to previous digest. * Note that this is four seperate 32-bit additions CLC LDA MD5TEMPB ADC DIGEST STA DIGEST LDA MD5TEMPB+1 ADC DIGEST+1 STA DIGEST+1 LDA MD5TEMPB+2 ADC DIGEST+2 STA DIGEST+2 LDA MD5TEMPB+3 ADC DIGEST+3 STA DIGEST+3 CLC LDA MD5TEMPB+4 ADC DIGEST+4 STA DIGEST+4 LDA MD5TEMPB+5 ADC DIGEST+5 STA DIGEST+5 LDA MD5TEMPB+6 ADC DIGEST+6 STA DIGEST+6 LDA MD5TEMPB+7 ADC DIGEST+7 STA DIGEST+7 CLC LDA MD5TEMPB+8 ADC DIGEST+8 STA DIGEST+8 LDA MD5TEMPB+9 ADC DIGEST+9 STA DIGEST+9 LDA MD5TEMPB+10 ADC DIGEST+10 STA DIGEST+10 LDA MD5TEMPB+11 ADC DIGEST+11 STA DIGEST+11 CLC LDA MD5TEMPB+12 ADC DIGEST+12 STA DIGEST+12 LDA MD5TEMPB+13 ADC DIGEST+13 STA DIGEST+13 LDA MD5TEMPB+14 ADC DIGEST+14 STA DIGEST+14 LDA MD5TEMPB+15 ADC DIGEST+15 STA DIGEST+15 RTS * Basic MD5 functions MD5LOADA LDA MD5TEMPB ;Put 'A' into temp variable STA MD5TEMPV LDA MD5TEMPB+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 STA MD5TEMPV+3 RTS MD5LOADB LDA MD5TEMPB+4 ;Put 'B' into temp variable STA MD5TEMPV LDA MD5TEMPB+5 STA MD5TEMPV+1 LDA MD5TEMPB+6 STA MD5TEMPV+2 LDA MD5TEMPB+7 STA MD5TEMPV+3 RTS MD5LOADC LDA MD5TEMPB+8 ;Put 'C' into temp variable STA MD5TEMPV LDA MD5TEMPB+9 STA MD5TEMPV+1 LDA MD5TEMPB+10 STA MD5TEMPV+2 LDA MD5TEMPB+11 STA MD5TEMPV+3 RTS MD5LOADD LDA MD5TEMPB+12 ;Put 'D' into temp variable STA MD5TEMPV LDA MD5TEMPB+13 STA MD5TEMPV+1 LDA MD5TEMPB+14 STA MD5TEMPV+2 LDA MD5TEMPB+15 STA MD5TEMPV+3 RTS MD5STORA LDA MD5TEMPV ;Store temp variable into 'A' in temp buffer STA MD5TEMPB LDA MD5TEMPV+1 STA MD5TEMPB+1 LDA MD5TEMPV+2 STA MD5TEMPB+2 LDA MD5TEMPV+3 STA MD5TEMPB+3 RTS MD5STORB LDA MD5TEMPV ;Store temp variable into 'B' STA MD5TEMPB+4 LDA MD5TEMPV+1 STA MD5TEMPB+5 LDA MD5TEMPV+2 STA MD5TEMPB+6 LDA MD5TEMPV+3 STA MD5TEMPB+7 RTS MD5STORC LDA MD5TEMPV ;Store temp variable into 'C' STA MD5TEMPB+8 LDA MD5TEMPV+1 STA MD5TEMPB+9 LDA MD5TEMPV+2 STA MD5TEMPB+10 LDA MD5TEMPV+3 STA MD5TEMPB+11 RTS MD5STORD LDA MD5TEMPV ;Store temp variable into 'D' STA MD5TEMPB+12 LDA MD5TEMPV+1 STA MD5TEMPB+13 LDA MD5TEMPV+2 STA MD5TEMPB+14 LDA MD5TEMPV+3 STA MD5TEMPB+15 RTS MD5ADDA CLC ;Add 'A' to temp variable LDA MD5TEMPB ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS MD5ADDB CLC ;Add 'B' to temp variable LDA MD5TEMPB+4 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+5 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+6 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+7 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS MD5ADDC CLC ;Add 'C' to temp variable LDA MD5TEMPB+8 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+9 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+10 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+11 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS MD5ADDD CLC ;Add 'D' to temp variable LDA MD5TEMPB+12 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+13 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+14 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+15 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS * F function: * F(X,Y,Z) = XY v not(X) Z F_BCD LDA MD5TEMPB+4 ;B&C AND MD5TEMPB+8 STA MD5TEMP2 LDA MD5TEMPB+5 AND MD5TEMPB+9 STA MD5TEMP2+1 LDA MD5TEMPB+6 AND MD5TEMPB+10 STA MD5TEMP2+2 LDA MD5TEMPB+7 AND MD5TEMPB+11 STA MD5TEMP2+3 CLC ;not(B)&D or (previous) -> MD5TEMPV+= LDA MD5TEMPB+4 EOR #$FF AND MD5TEMPB+12 ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+5 ; EOR #$FF AND MD5TEMPB+13 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+6 ; EOR #$FF AND MD5TEMPB+14 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+7 ; EOR #$FF AND MD5TEMPB+15 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS F_ABC LDA MD5TEMPB ;A&B AND MD5TEMPB+4 STA MD5TEMP2 LDA MD5TEMPB+1 AND MD5TEMPB+5 STA MD5TEMP2+1 LDA MD5TEMPB+2 AND MD5TEMPB+6 STA MD5TEMP2+2 LDA MD5TEMPB+3 AND MD5TEMPB+7 STA MD5TEMP2+3 CLC ;not(A)&C or (previous) -> MD5TEMPV+= LDA MD5TEMPB EOR #$FF AND MD5TEMPB+8 ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 ; EOR #$FF AND MD5TEMPB+9 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 ; EOR #$FF AND MD5TEMPB+10 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 ; EOR #$FF AND MD5TEMPB+11 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS F_DAB LDA MD5TEMPB+12 ;D&A AND MD5TEMPB STA MD5TEMP2 LDA MD5TEMPB+13 AND MD5TEMPB+1 STA MD5TEMP2+1 LDA MD5TEMPB+14 AND MD5TEMPB+2 STA MD5TEMP2+2 LDA MD5TEMPB+15 AND MD5TEMPB+3 STA MD5TEMP2+3 CLC ;not(D)&B or (previous) -> MD5TEMPV+= LDA MD5TEMPB+12 EOR #$FF AND MD5TEMPB+4 ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+13 ; EOR #$FF AND MD5TEMPB+5 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+14 ; EOR #$FF AND MD5TEMPB+6 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+15 ; EOR #$FF AND MD5TEMPB+7 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS F_CDA LDA MD5TEMPB+8 ;C&D AND MD5TEMPB+12 STA MD5TEMP2 LDA MD5TEMPB+9 AND MD5TEMPB+13 STA MD5TEMP2+1 LDA MD5TEMPB+10 AND MD5TEMPB+14 STA MD5TEMP2+2 LDA MD5TEMPB+11 AND MD5TEMPB+15 STA MD5TEMP2+3 CLC ;not(C)&A or (previous) -> MD5TEMPV+= LDA MD5TEMPB+8 EOR #$FF AND MD5TEMPB ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+9 ; EOR #$FF AND MD5TEMPB+1 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+10 ; EOR #$FF AND MD5TEMPB+2 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+11 ; EOR #$FF AND MD5TEMPB+3 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS * G Function: * G(X,Y,Z) = XZ v Y not(Z) G_BCD LDA MD5TEMPB+4 ;B&D AND MD5TEMPB+12 STA MD5TEMP2 LDA MD5TEMPB+5 AND MD5TEMPB+13 STA MD5TEMP2+1 LDA MD5TEMPB+6 AND MD5TEMPB+14 STA MD5TEMP2+2 LDA MD5TEMPB+7 AND MD5TEMPB+15 STA MD5TEMP2+3 CLC ;not(D)&C or (previous) -> MD5TEMPV+= LDA MD5TEMPB+12 EOR #$FF AND MD5TEMPB+8 ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+13 ; EOR #$FF AND MD5TEMPB+9 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+14 ; EOR #$FF AND MD5TEMPB+10 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+15 ; EOR #$FF AND MD5TEMPB+11 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS G_ABC LDA MD5TEMPB ;A&C AND MD5TEMPB+8 STA MD5TEMP2 LDA MD5TEMPB+1 AND MD5TEMPB+9 STA MD5TEMP2+1 LDA MD5TEMPB+2 AND MD5TEMPB+10 STA MD5TEMP2+2 LDA MD5TEMPB+3 AND MD5TEMPB+11 STA MD5TEMP2+3 CLC ;not(C)&B or (previous) -> MD5TEMPV+= LDA MD5TEMPB+8 EOR #$FF AND MD5TEMPB+4 ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+9 ; EOR #$FF AND MD5TEMPB+5 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+10 ; EOR #$FF AND MD5TEMPB+6 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+11 ; EOR #$FF AND MD5TEMPB+7 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS G_DAB LDA MD5TEMPB+4 ;B&D AND MD5TEMPB+12 STA MD5TEMP2 LDA MD5TEMPB+5 AND MD5TEMPB+13 STA MD5TEMP2+1 LDA MD5TEMPB+6 AND MD5TEMPB+14 STA MD5TEMP2+2 LDA MD5TEMPB+7 AND MD5TEMPB+15 STA MD5TEMP2+3 CLC ;not(B)&A or (previous) -> MD5TEMPV+= LDA MD5TEMPB+4 EOR #$FF AND MD5TEMPB ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+5 ; EOR #$FF AND MD5TEMPB+1 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+6 ; EOR #$FF AND MD5TEMPB+2 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+7 ; EOR #$FF AND MD5TEMPB+3 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS G_CDA LDA MD5TEMPB ;C&A AND MD5TEMPB+8 STA MD5TEMP2 LDA MD5TEMPB+1 AND MD5TEMPB+9 STA MD5TEMP2+1 LDA MD5TEMPB+2 AND MD5TEMPB+10 STA MD5TEMP2+2 LDA MD5TEMPB+3 AND MD5TEMPB+11 STA MD5TEMP2+3 CLC ;not(A)&D or (previous) -> MD5TEMPV+= LDA MD5TEMPB EOR #$FF AND MD5TEMPB+12 ORA MD5TEMP2 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 ; EOR #$FF AND MD5TEMPB+13 ORA MD5TEMP2+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 ; EOR #$FF AND MD5TEMPB+14 ORA MD5TEMP2+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 ; EOR #$FF AND MD5TEMPB+15 ORA MD5TEMP2+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS * H function: * H(X,Y,Z) = X xor Y xor Z H_BCD CLC ;BxCxD LDA MD5TEMPB+4 EOR MD5TEMPB+8 EOR MD5TEMPB+12 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+5 EOR MD5TEMPB+9 EOR MD5TEMPB+13 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+6 EOR MD5TEMPB+10 EOR MD5TEMPB+14 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+7 EOR MD5TEMPB+11 EOR MD5TEMPB+15 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS H_ABC CLC ;AxBxC LDA MD5TEMPB EOR MD5TEMPB+4 EOR MD5TEMPB+8 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 EOR MD5TEMPB+5 EOR MD5TEMPB+9 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 EOR MD5TEMPB+6 EOR MD5TEMPB+10 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 EOR MD5TEMPB+7 EOR MD5TEMPB+11 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS H_DAB CLC ;AxBxD LDA MD5TEMPB EOR MD5TEMPB+4 EOR MD5TEMPB+12 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 EOR MD5TEMPB+5 EOR MD5TEMPB+13 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 EOR MD5TEMPB+6 EOR MD5TEMPB+14 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 EOR MD5TEMPB+7 EOR MD5TEMPB+15 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS H_CDA CLC ;AxCxD LDA MD5TEMPB EOR MD5TEMPB+8 EOR MD5TEMPB+12 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 EOR MD5TEMPB+9 EOR MD5TEMPB+13 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 EOR MD5TEMPB+10 EOR MD5TEMPB+14 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 EOR MD5TEMPB+11 EOR MD5TEMPB+15 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS * I function * I(X,Y,Z) = Y xor (X v not(Z)) I_BCD CLC ~D|B^C LDA MD5TEMPB+12 EOR #$FF ORA MD5TEMPB+4 EOR MD5TEMPB+8 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+13 EOR #$FF ORA MD5TEMPB+5 EOR MD5TEMPB+9 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+14 EOR #$FF ORA MD5TEMPB+6 EOR MD5TEMPB+10 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+15 EOR #$FF ORA MD5TEMPB+7 EOR MD5TEMPB+11 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS I_ABC CLC ~C|A^B LDA MD5TEMPB+8 EOR #$FF ORA MD5TEMPB EOR MD5TEMPB+4 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+9 EOR #$FF ORA MD5TEMPB+1 EOR MD5TEMPB+5 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+10 EOR #$FF ORA MD5TEMPB+2 EOR MD5TEMPB+6 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+11 EOR #$FF ORA MD5TEMPB+3 EOR MD5TEMPB+7 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS I_DAB CLC ~B|D^A LDA MD5TEMPB+4 EOR #$FF ORA MD5TEMPB+12 EOR MD5TEMPB ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+5 EOR #$FF ORA MD5TEMPB+13 EOR MD5TEMPB+1 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+6 EOR #$FF ORA MD5TEMPB+14 EOR MD5TEMPB+2 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+7 EOR #$FF ORA MD5TEMPB+15 EOR MD5TEMPB+3 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS I_CDA CLC ~A|C^D LDA MD5TEMPB EOR #$FF ORA MD5TEMPB+8 EOR MD5TEMPB+12 ADC MD5TEMPV STA MD5TEMPV LDA MD5TEMPB+1 EOR #$FF ORA MD5TEMPB+9 EOR MD5TEMPB+13 ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5TEMPB+2 EOR #$FF ORA MD5TEMPB+10 EOR MD5TEMPB+14 ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5TEMPB+3 EOR #$FF ORA MD5TEMPB+11 EOR MD5TEMPB+15 ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS *Rotate left functions MD5RL LDA MD5TEMPV ;Rotate the 32-bit temp var left by one bit ASL STA MD5TEMPV LDA MD5TEMPV+1 ROL STA MD5TEMPV+1 LDA MD5TEMPV+2 ROL STA MD5TEMPV+2 LDA MD5TEMPV+3 ROL STA MD5TEMPV+3 LDA MD5TEMPV ;Take high bit and wrap around; ADC #0 ; add it to empty position in lowest byte STA MD5TEMPV RTS * This is somewhat sloppy but it works * It should be optimized to use full byte shifts when possible. MD5RL7 LUP 7 JSR MD5RL --^ RTS MD5RL12 LUP 12 JSR MD5RL --^ RTS MD5RL17 LUP 17 JSR MD5RL --^ RTS MD5RL22 LUP 22 JSR MD5RL --^ RTS MD5RL5 LUP 5 JSR MD5RL --^ RTS MD5RL9 LUP 9 JSR MD5RL --^ RTS MD5RL14 LUP 14 JSR MD5RL --^ RTS MD5RL20 LUP 20 JSR MD5RL --^ RTS MD5RL4 LUP 4 JSR MD5RL --^ RTS MD5RL11 LUP 11 JSR MD5RL --^ RTS MD5RL16 LUP 16 JSR MD5RL --^ RTS MD5RL23 LUP 23 JSR MD5RL --^ RTS MD5RL6 LUP 6 JSR MD5RL --^ RTS MD5RL10 LUP 10 JSR MD5RL --^ RTS MD5RL15 LUP 15 JSR MD5RL --^ RTS MD5RL21 LUP 21 JSR MD5RL --^ RTS *Get data from input block and add it to temp variable MD5ADDX ASL ASL CLC ;It better not be greater than 16 anyway! TAX LDA MD5BUFR,X ADC MD5TEMPV STA MD5TEMPV LDA MD5BUFR+1,X ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5BUFR+2,X ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5BUFR+3,X ADC MD5TEMPV+3 STA MD5TEMPV+3 RTS *Get next element from table and add it to temp variable NEXT_T LDX MD5TP CLC LDA MD5T+3,X ;reverse byte order ADC MD5TEMPV STA MD5TEMPV LDA MD5T+2,X ADC MD5TEMPV+1 STA MD5TEMPV+1 LDA MD5T+1,X ADC MD5TEMPV+2 STA MD5TEMPV+2 LDA MD5T,X ADC MD5TEMPV+3 STA MD5TEMPV+3 INX INX INX INX STX MD5TP RTS * MD5 Sine Constants * The following is the 64-element MD5 table T[1 ... 64] constructed from * the sine function. Let T[i] denote the i-th element of the table, which * is equal to the integer part of 2^32, or 4294967296, times abs(sin(i)), * where i is in radians. * * Sorry, Colin, no occult messages here. :) * These need to be re-arranged to LSB-first * (which is done by the NEXT_T subroutine) MD5TP HEX 00 ;Pointer to current element in table below MD5T * /* Round 1 */ HEX D76AA478 ; /* 1 */ HEX E8C7B756 ; /* 2 */ HEX 242070DB ; /* 3 */ HEX C1BDCEEE ; /* 4 */ HEX F57C0FAF ; /* 5 */ HEX 4787C62A ; /* 6 */ HEX A8304613 ; /* 7 */ HEX FD469501 ; /* 8 */ HEX 698098D8 ; /* 9 */ HEX 8B44F7AF ; /* 10 */ HEX FFFF5BB1 ; /* 11 */ HEX 895CD7BE ; /* 12 */ HEX 6B901122 ; /* 13 */ HEX FD987193 ; /* 14 */ HEX A679438E ; /* 15 */ HEX 49B40821 ; /* 16 */ * /* Round 2 */ HEX F61E2562 ; /* 17 */ HEX C040B340 ; /* 18 */ HEX 265E5A51 ; /* 19 */ HEX E9B6C7AA ; /* 20 */ HEX D62F105D ; /* 21 */ HEX 02441453 ; /* 22 */ HEX D8A1E681 ; /* 23 */ HEX E7D3FBC8 ; /* 24 */ HEX 21E1CDE6 ; /* 25 */ HEX C33707D6 ; /* 26 */ HEX F4D50D87 ; /* 27 */ HEX 455A14ED ; /* 28 */ HEX A9E3E905 ; /* 29 */ HEX FCEFA3F8 ; /* 30 */ HEX 676F02D9 ; /* 31 */ HEX 8D2A4C8A ; /* 32 */ * /* Round 3 */ HEX FFFA3942 ; /* 33 */ HEX 8771F681 ; /* 34 */ HEX 6D9D6122 ; /* 35 */ HEX FDE5380C ; /* 36 */ HEX A4BEEA44 ; /* 37 */ HEX 4BDECFA9 ; /* 38 */ HEX F6BB4B60 ; /* 39 */ HEX BEBFBC70 ; /* 40 */ HEX 289B7EC6 ; /* 41 */ HEX EAA127FA ; /* 42 */ HEX D4EF3085 ; /* 43 */ HEX 04881D05 ; /* 44 */ HEX D9D4D039 ; /* 45 */ HEX E6DB99E5 ; /* 46 */ HEX 1FA27CF8 ; /* 47 */ HEX C4AC5665 ; /* 48 */ * /* Round 4 */ HEX F4292244 ; /* 49 */ HEX 432AFF97 ; /* 50 */ HEX AB9423A7 ; /* 51 */ HEX FC93A039 ; /* 52 */ HEX 655B59C3 ; /* 53 */ HEX 8F0CCC92 ; /* 54 */ HEX FFEFF47D ; /* 55 */ HEX 85845DD1 ; /* 56 */ HEX 6FA87E4F ; /* 57 */ HEX FE2CE6E0 ; /* 58 */ HEX A3014314 ; /* 59 */ HEX 4E0811A1 ; /* 60 */ HEX F7537E82 ; /* 61 */ HEX BD3AF235 ; /* 62 */ HEX 2AD7D2BB ; /* 63 */ HEX EB86D391 ; /* 64 */

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Identical Password and Member ID
by Travel Group Email Account 17 Dec '03

17 Dec '03

Dear Joe, Our records show that your Expedia account contains a member ID and password that are identical. While we understand that this makes it simpler for you to remember them, we are now asking our members to create passwords that do not match their member ID's. We appreciate your assistance in this small change, which increases the security of your account. You can change your password by following these steps: 1. Access your Expedia Member Information http://expedia.msn.com/pub/signup.dll?qscr=uupd 2. Click Continue on the Expedia sign in screen. 3. If prompted, enter current member ID and password, and then click Continue. 4. Click Continue on the secure sign in screen. 5. Follow instructions for section labeled 3 of 6: Password. 6. Click Continue. Thank you for using Expedia. Please feel free to contact us if you have any questions.

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ANY OF YOUR ANSWERS YES?
by BIZ-BEST＠profits.com 17 Dec '03

17 Dec '03

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