Re: infinity & set membership (fwd)
17 Dec
2003
17 Dec
'03
11:17 p.m.
What could be the problem here? One problem might be that an integer (not including infinity) divided by "infinity" should be 0.
This ratio has one of 3 outcomes in my system depending on the rate of approach to infinity of the defining functions, oo/oo = 0 if the denominator grows faster than the numerator oo/oo = oo if the numerator grows faster than the denominator oo/oo = 1 if the two functions grow at equal rates Jim Choate CyberTects ravage@ssz.com
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Jim Choate