Re: smaller f00f.c
Adam says:
Hey, challenge is on:
main(){int i=0xc8c70ff0;void (*f)()=&i;f();} /* f00fies 44 char */ main(){((int(*)())"\360\017\307\310")();} main(){int i=0xc8c70ff0,(*f)()=&i;f();} main(i){int(*f)()=&i;i=0xc8c70ff0;f();} main(i){i=0xc8c70ff0;((int(*)())&i)();} (*f)();main(i){f=&i;i=0xc8c70ff0;f();} (*f)()="\360\017\307\310";main(){f();} /* 38 chars */
Compiled with gcc.
long main=0xc8c70ff0; /* also gcc; 21 chars, and not my invention */ Without the "long" you get a warning, but it compiles anyway... 16 chars. Jim Gillogly jim@acm.org
Jim Gillogly
Adam says:
(*f)()="\360\017\307\310";main(){f();} /* 38 chars */
Compiled with gcc.
long main=0xc8c70ff0; /* also gcc; 21 chars, and not my invention */ Without the "long" you get a warning, but it compiles anyway... 16 chars.
Wow! Completely out-classed :-)
I did try this one in my efforts:
main="\360\017\307\310";
which compiles, but obviously doesn't work.
So... I see the light now: you can write var=5; and it'll assume int,
and so if you do main=5; it will create asm label _main against a
memory location initialised to that constant ... due to lack of type
checking, that'll make the linker happy and voila. Excellent.
Adam
--
Now officially an EAR violation...
Have *you* exported RSA today? --> http://www.dcs.ex.ac.uk/~aba/rsa/
print pack"C*",split/\D+/,`echo "16iII*o\U@{$/=$z;[(pop,pop,unpack"H*",<>
)]}\EsMsKsN0[lN*1lK[d2%Sa2/d0
participants (2)
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Adam Back
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jim@mentat.com