[wrong] [ot] crazy journal

Karl gmkarl at gmail.com
Sun May 30 13:09:31 PDT 2021

So, with the bin filling decisions, do we want hoe many ordered lists there
are, or how many unordered sets there are?

Changing the order of the decisions doesn't make a new possible outcome.
To calculate how many possible outcomes there are, we keep the decision
order fixed.

So, we want combinations here.

The number of ways to fill a histogram bin to binheight appears to be
(sampcount C binheight) popcount ^ (sampcount - binheight), but I'm not
sure !
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