HELP ME, PLEASE, I CAN�T WITH THIS INFORMATION. !!GETTINGS!!

Agapito lopezcaste el_super_sayajin at hotmail.com
Tue Apr 17 00:47:57 PDT 2001


nesecito ayuda quien me puede asesorar sobre este tipo de informacion
aaaaaahhhhhh por cierto los mensajes del enanito como puedo abrir el codigo 
de este mensaje.

>COMMAND
>
>     Novell Remote.NLM Password Decryption Algorithm
>
>SYSTEMS AFFECTED
>
>     Novell Netware
>
>PROBLEM
>
>     'dreamer' found following.  Novell is known to use a one-way  hash
>     algorithm in their password encryption, so all captured  encrypted
>     passwords must be brute-forced, slowly and painfully.  However,  a
>     few  days  ago,  he  cryptographically cracked Novell's Remote.NLM
>     password  encryption  algorithm.   It  is  a  very  weak algorithm
>     compared  to  what  Novell  has  implemented  in  NDS,  as  it  is
>     instantaneously  decryptable.   RConsole  password  encryption  is
>     different from Remote.NLM password encryption because:
>
>     1) Encrypted  RConsole  passwords  are  sent across the wire,  via
>        RConsole.   Remote.NLM's encrypted  passwords are  generated at
>        the server console  by typing REMOTE  ENCRYPT MyPass, and  they
>        are optionally stored in SYS:System\LDRemote.NCF.
>
>     2) They use a  different password encryption algorithm.   RConsole
>        passwords are encrypted  with information from  the workstation
>        that is currently running  RConsole.  Remote.NLM passwords  are
>        encrypted with  a time  byte, one  of 255  constants in  a hash
>        table,  appended   characters,  some   XORing,  and   bit-order
>        separation.
>
>     3) Encrypted RConsole passwords are locally obtained with a packet
>        sniffer, but  Remote.NLM passwords  are remotely  accessible to
>        anyone with the ability to view SYS:System\LDRemote.NCF.
>
>     The Remote.NLM passwords are decrypted using only five steps.   To
>     encrypt,  simply  reverse  the  steps.   The  password  will  look
>     something like this:
>
>         AF8CBBF48CA9955F5ADAFDADAA23
>
>     The structure of the password is as follows:
>
>         AF8CBBF48CA99 55F5ADAFDADAA - 23
>
>     The first section contains the low-order bits, and the second, the
>     high-order bits.  23 is the time byte, which is decremented by the
>     server once every two seconds, from FF to 02, then back up to  FF,
>     etc.
>
>     Step 1)  Realign the low-order bits and high-order bits
>     =======================================================
>     This is extremely simple to do.  The high-order bits are in  order
>     from the  first character  to the  last, and  so are the low-order
>     bits.  Example:
>
>         Password: AF8CBBF48CA99 - 55F5ADAFDADAA,
>         Output: 5A 5F F8 5C AB DB AF F4 D8 AC DA A9 A9
>
>     At this point, ignore 5A 5F F8 5C, or the first four bytes.   They
>     are appended somewhere during  encryption, and decrypt to  "%*@$".
>     It  was  a  TERRIBLE  idea  for  Novell  to  implement  those four
>     characters into  every single  password, as  those are  what helps
>     rebuild their hash table from scratch.  Also, if the length of the
>     password is 10, the password is automatically decryptable to nul.
>
>     Step 2)
>     =======
>     Match  each  of  the  password   characters  (group  of  two   hex
>     characters) to the hash table below.  Use their position from  the
>     beginning of  the table  to determine  the value  of the  pre-hash
>     encrypted  password.   Example:  F4,  the  8th  character  of  the
>     password, matches the hash table at 95.  This means that 95 is the
>     pre-hash  value  of  F4.   Thus  far,  (ignoring  the  first  four
>     characters) the password was:
>
>         AB DB AF F4 D8 AC DA A9 A9
>
>     and now the password is:
>
>         98 A0 9B 95 A1 9D A6 9C 9C
>
>     Remote.NLM Hash Table
>
>             00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
>
>         00  5B 58 5E 5F 59 5C 5A 5D-73 70 76 77 71 74 72 75
>         10  13 10 16 17 11 14 12 15-7B 78 7E 7F 79 7C 7A 7D
>         20  53 50 56 57 51 54 52 55-03 00 06 07 01 04 02 05
>         30  1B 18 1E 1F 19 1C 1A 1D-0B 08 0E 0F 09 0C 0A 0D
>         40  2B 28 2E 2F 29 2C 2A 2D-63 60 66 67 61 64 62 65
>         50  83 80 86 87 81 84 82 85-3B 38 3E 3F 39 3C 3A 3D
>         60  8B 88 8E 8F 89 8C 8A 8D-33 30 36 37 31 34 32 35
>         70  93 90 96 97 91 94 92 95-6B 68 6E 6F 69 6C 6A 6D
>         80  9B 98 9E 9F 99 9C 9A 9D-A3 A0 A6 A7 A1 A4 A2 A5
>         90  F3 F0 F6 F7 F1 F4 F2 F5-AB A8 AE AF A9 AC AA AD
>         A0  DB D8 DE DF D9 DC DA DD-FB F8 FE FF F9 FC FA FD
>         B0  23 20 26 27 21 24 22 25-B3 B0 B6 B7 B1 B4 B2 B5
>         C0  CB C8 CE CF C9 CC CA CD-BB B8 BE BF B9 BC BA BD
>         D0  C3 C0 C6 C7 C1 C4 C2 C5-D3 D0 D6 D7 D1 D4 D2 D5
>         E0  43 40 46 47 41 44 42 45-E3 E0 E6 E7 E1 E4 E2 E5
>         F0  4B 48 4E 4F 49 4C 4A 4D-EB E8 EE EF E9 EC EA ED
>
>     Step 3)
>     =======
>     Subtract  the  length  (the  number  of  groups of hex characters,
>     excluding  the  time  character)  of  the  full password from each
>     encrypted password character.   Now you have  the ACTUAL  pre-hash
>     encrypted  password.   If  the  subtracted  value is negative then
>     simply continue from FF down to the negative value.  Example:   if
>     the password character is at 04, and the length is 6, the value of
>     the password character will be FF.   The length is 13 (D in  hex),
>     so the password was:
>
>         98 A0 9B 95 A1 9D A6 9C 9C
>
>     and is now:
>
>         8B 93 8E 88 94 90 99 8F 8F
>
>     Step 4)
>     =======
>     Get the  time var,  in this  situation 23  (hex), and  subtract it
>     from FF.  This new character is for use in Step 5.  Example:
>
>         FF-23=DC.
>
>     Step 5)
>     =======
>     Finally, XOR  each character  (group of  2 hex  characters) of the
>     encrypted password with the new  time character, and you now  have
>     the decrypted password!  The password was:
>
>         8B 93 8E 88 94 90 99 8F 8F  (before the XOR)
>
>     Now, the decrypted password is:
>
>         57 4F 52 54 48 4C 45 53 53
>
>     "WORTHLESS"
>
>     TheRuiner ('dreamer') has  written a program  in Pascal (oh  well)
>     which  decrypts  Remote.NLM  passwords  instantaneously.   It  was
>     tested  on  a  password  of  around  50  characters, and it worked
>     flawlessly,  so  there  shouldn't  be  anything  to  worry   about
>     regarding the length limit.  It can decrypt any character, from 00
>     to FF, and it will display that value upon execution.  The  source
>     of the program is below.
>
>     ---
>     Content-Type: application/octet-stream; name="remote.zip"
>     Content-Transfer-Encoding: base64
>     Content-Disposition: inline; filename="remote.zip"
>     Content-MD5: GJdEvw/Ya/aVRkxDK1lSyg==
>
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>
>     -----
>
>SOLUTION
>
>     Nothing yet.
>gettings for all.
>bye
>
>
>Send FREE April Fool's Greetings to your friends!
>http://www.whowhere.lycos.com/redirects/American_Greetings.rdct

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