infinity & set membership (fwd)
Jim Choate
ravage at EINSTEIN.ssz.com
Mon Jan 20 07:33:51 PST 1997
> What could be the problem here? One problem might be that an integer
> (not including infinity) divided by "infinity" should be 0.
This ratio has one of 3 outcomes in my system depending on the rate of
approach to infinity of the defining functions,
oo/oo = 0 if the denominator grows faster than the numerator
oo/oo = oo if the numerator grows faster than the denominator
oo/oo = 1 if the two functions grow at equal rates
Jim Choate
CyberTects
ravage at ssz.com
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