10 Nov
2022
10 Nov
'22
4:43 p.m.
freq[k] = sum_over_n(time[n] * exp(-2 * pi * i * k * n / N) time[n] = 1/N * sum_over_k(freq[k] * exp(2 * pi * i * k * n / N) yay sums could be transformed to array operations