On Fri, 05 Aug 2016 07:11:11 +0100 oshwm <oshwm@openmailbox.org> wrote:
would the case for no data travel require that both particles exist in the same space and time? also, if measuring a quantum object changes it, can you not measure twice or similar using the measurements to both derive its original state and return it to its original state?
Going by BF's description, states don't really matter. All that matters is that you can do something to one of the particles and that action triggers a change in the other particle, a change that you can detect. If you can do something 'at will' to one particle, and then detect a change in the other particle, you have transmitted one bit.
(yep, now the schoolboy physicists are getting involved :D )
Ever heard stories about naked rulers, or emperors without clothes?
On 5 August 2016 06:58:15 BST, juan <juan.g71@gmail.com> wrote:
On Fri, 05 Aug 2016 07:19:19 +0200 Bastiani Fortress <bastianifortress@yandex.com> wrote:
As i can remember, the point was when two particles are entangled, they bear the same quantum state, and they simultaneously shift their states önce either of them is "observed".
OK.
So you know that the other twin is in the same state, but you cannot code it at will,
Not sure what you mean by "code it".
and since you don't know its first state without having "observed" it, you cannot determine whether the other twin has been observed or not
And now I'm even more confused =P
But let's go back to your first sentence. You have a couple of 'entangled' particles. Trying to measure particle 'A' triggers a change in particle 'B' - is that what you are saying?
If that's the case, then you do have 'information transfer' - one bit.
(that would be 1 bit of data streaming).
This is what i remember from what i read years ago, please correct me if i'm wrong.