nesecito ayuda quien me puede asesorar sobre este tipo de informacion aaaaaahhhhhh por cierto los mensajes del enanito como puedo abrir el codigo de este mensaje.

COMMAND

Novell Remote.NLM Password Decryption Algorithm

SYSTEMS AFFECTED

Novell Netware

PROBLEM

'dreamer' found following. Novell is known to use a one-way hash algorithm in their password encryption, so all captured encrypted passwords must be brute-forced, slowly and painfully. However, a few days ago, he cryptographically cracked Novell's Remote.NLM password encryption algorithm. It is a very weak algorithm compared to what Novell has implemented in NDS, as it is instantaneously decryptable. RConsole password encryption is different from Remote.NLM password encryption because:

1) Encrypted RConsole passwords are sent across the wire, via RConsole. Remote.NLM's encrypted passwords are generated at the server console by typing REMOTE ENCRYPT MyPass, and they are optionally stored in SYS:System\LDRemote.NCF.

2) They use a different password encryption algorithm. RConsole passwords are encrypted with information from the workstation that is currently running RConsole. Remote.NLM passwords are encrypted with a time byte, one of 255 constants in a hash table, appended characters, some XORing, and bit-order separation.

3) Encrypted RConsole passwords are locally obtained with a packet sniffer, but Remote.NLM passwords are remotely accessible to anyone with the ability to view SYS:System\LDRemote.NCF.

The Remote.NLM passwords are decrypted using only five steps. To encrypt, simply reverse the steps. The password will look something like this:

AF8CBBF48CA9955F5ADAFDADAA23

The structure of the password is as follows:

AF8CBBF48CA99 55F5ADAFDADAA - 23

The first section contains the low-order bits, and the second, the high-order bits. 23 is the time byte, which is decremented by the server once every two seconds, from FF to 02, then back up to FF, etc.

Step 1) Realign the low-order bits and high-order bits ======================================================= This is extremely simple to do. The high-order bits are in order from the first character to the last, and so are the low-order bits. Example:

Password: AF8CBBF48CA99 - 55F5ADAFDADAA, Output: 5A 5F F8 5C AB DB AF F4 D8 AC DA A9 A9

At this point, ignore 5A 5F F8 5C, or the first four bytes. They are appended somewhere during encryption, and decrypt to "%*@$". It was a TERRIBLE idea for Novell to implement those four characters into every single password, as those are what helps rebuild their hash table from scratch. Also, if the length of the password is 10, the password is automatically decryptable to nul.

Step 2) ======= Match each of the password characters (group of two hex characters) to the hash table below. Use their position from the beginning of the table to determine the value of the pre-hash encrypted password. Example: F4, the 8th character of the password, matches the hash table at 95. This means that 95 is the pre-hash value of F4. Thus far, (ignoring the first four characters) the password was:

AB DB AF F4 D8 AC DA A9 A9

and now the password is:

98 A0 9B 95 A1 9D A6 9C 9C

Remote.NLM Hash Table

00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F

00 5B 58 5E 5F 59 5C 5A 5D-73 70 76 77 71 74 72 75 10 13 10 16 17 11 14 12 15-7B 78 7E 7F 79 7C 7A 7D 20 53 50 56 57 51 54 52 55-03 00 06 07 01 04 02 05 30 1B 18 1E 1F 19 1C 1A 1D-0B 08 0E 0F 09 0C 0A 0D 40 2B 28 2E 2F 29 2C 2A 2D-63 60 66 67 61 64 62 65 50 83 80 86 87 81 84 82 85-3B 38 3E 3F 39 3C 3A 3D 60 8B 88 8E 8F 89 8C 8A 8D-33 30 36 37 31 34 32 35 70 93 90 96 97 91 94 92 95-6B 68 6E 6F 69 6C 6A 6D 80 9B 98 9E 9F 99 9C 9A 9D-A3 A0 A6 A7 A1 A4 A2 A5 90 F3 F0 F6 F7 F1 F4 F2 F5-AB A8 AE AF A9 AC AA AD A0 DB D8 DE DF D9 DC DA DD-FB F8 FE FF F9 FC FA FD B0 23 20 26 27 21 24 22 25-B3 B0 B6 B7 B1 B4 B2 B5 C0 CB C8 CE CF C9 CC CA CD-BB B8 BE BF B9 BC BA BD D0 C3 C0 C6 C7 C1 C4 C2 C5-D3 D0 D6 D7 D1 D4 D2 D5 E0 43 40 46 47 41 44 42 45-E3 E0 E6 E7 E1 E4 E2 E5 F0 4B 48 4E 4F 49 4C 4A 4D-EB E8 EE EF E9 EC EA ED

Step 3) ======= Subtract the length (the number of groups of hex characters, excluding the time character) of the full password from each encrypted password character. Now you have the ACTUAL pre-hash encrypted password. If the subtracted value is negative then simply continue from FF down to the negative value. Example: if the password character is at 04, and the length is 6, the value of the password character will be FF. The length is 13 (D in hex), so the password was:

98 A0 9B 95 A1 9D A6 9C 9C

and is now:

8B 93 8E 88 94 90 99 8F 8F

Step 4) ======= Get the time var, in this situation 23 (hex), and subtract it from FF. This new character is for use in Step 5. Example:

FF-23=DC.

Step 5) ======= Finally, XOR each character (group of 2 hex characters) of the encrypted password with the new time character, and you now have the decrypted password! The password was:

8B 93 8E 88 94 90 99 8F 8F (before the XOR)

Now, the decrypted password is:

57 4F 52 54 48 4C 45 53 53

"WORTHLESS"

TheRuiner ('dreamer') has written a program in Pascal (oh well) which decrypts Remote.NLM passwords instantaneously. It was tested on a password of around 50 characters, and it worked flawlessly, so there shouldn't be anything to worry about regarding the length limit. It can decrypt any character, from 00 to FF, and it will display that value upon execution. The source of the program is below.

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SOLUTION

Nothing yet. gettings for all. bye

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