AwakenToMe@aol.com, in a profound display of stubbornness, continues to insist that his program to enumerate all possible words of length N (that is, aaaaa, aaaab, aaaac, etc.) is somehow interesting. I am therefore forced to drive in the nail with a sledgehammer. Forgive me.
------Cut Here------ /* This could be more elegant, but the point is obviousness. */ #include <stdio.h>
int main() { char i[6];
for (i[0] = 'a'; i[0] < 'z'; i[0]++) for (i[1] = 'a'; i[1] < 'z'; i[1]++) for (i[2] = 'a'; i[2] < 'z'; i[2]++) for (i[3] = 'a'; i[3] < 'z'; i[3]++) for (i[4] = 'a'; i[4] < 'z'; i[4]++) printf("%s\n", i); } ------Cut Here------
Perry
I agree with you, but it could also be correct. Since the char array is allocated on the stack as an auto, its contents are not guaranteed. So i[5]='\0'; is needed as the first statement. And of course it will never include a 'z' because the '<' will not permit it. Replace all the '<' with '<='. Plus there is the small matter of non-ASCII character representations breaking the increments and comparisons. Oh, and don't forget that main() returns an integer. This will generate at least a warning from the compiler, since the code does not return anything. It may well return a random number or something that will be interpreted as an error code. (also less than a minute's work) ------------------------------------------------------------------------- Steven Weller | Technology (n): | | A substitute for adulthood. stevenw@best.com | Popular with middle-aged men.